Bag a contains red, white and blue marbles such that the red to white marble ratio is 1: 3 and the white to blue marble ratio is 2: 3. bag b contains red and white marbles in the ratio of 1: 4. together, the two bags contain 30 white marbles. how many red marbles could be in bag a?

There are 6 red marbles in Bag A.

Step-by-step explanation:

Bag A

Red to white marble ratio is 1:3

White to blue marble ratio is 2:3

If we match the amount of white marbles between both ratios we can put together a three-term ratio.

Red to White 2:6

White to Blue 6:9

Red to White to Blue 2:6:9

Then, the total amount of marbles in bag A is given by:

A= 2·x + 6·x + 9·x

Bag B

B= 1·x + 4·x

White marbles

Since the two bags contain 30 white marbles:

30== 6·x + 4·x=10x ⇒ x=3

Then,

:red marbles in bag A

=2·x=2·3=6

There are 6 red marbles in Bag A.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!