7x+4y=5 find the slope of a line parallel and perpendicular

To find the slope of a line parallel, you must firs of all make y the subject of the formula i.e

subtract 7x from both side of the equation

which implies : 7x -7x+4y = 5 - 7x

                      so,           4y = 5 - 7x

Divide both side by 4, since you are to make y to stand alone

This implies                    y = 5/4  - 7x/4.

Recall: If M1 represent a slope and M2 represent another slope, if they are parallel , then M1 = M2 and if they are perpendicular, then M1 = -1/M2

SO, the slope parallel = -7/4

And the slope perpendicular = -1 divided by -7/4

which implies                          -1 x -4/7

                                                 = 4/7

Step-by-step explanation:

Step-by-step explanation:

7x+4y=5

     4Y = -7X +5

       y = -7/4x + 5/4

Slope m₁ =-7/4

Slope of the line parallel to this line m₂ = -7/4

Slope (m₃) of the line perpendicular to this line   m₃= 4/7

  m₁  * m₃ = -1

 -7/4 * m₃  = -1

         m₃  = -1 * (-4/7) = 4/7

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group