The graph of f(x) = x² + 6x is shown. use the
graph to determine how many real solutions
the following equations have: x2 + 6x +6=0,
x+ 6x +9= 0, and x2 + 6x + 12 = 0. explain.

there are no figures how am i supposed to answer this question

step-by-step explanation:

i dont know

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.