You have a solution containing 10% acid and a solution containing 30% acid. how much of the 30% solution must you add to 1 liter of the 10% solution to create a mixture that is 22% acid?

Step-by-step explanation:

Let

x ----> liters of 30% solution needed

we know that

The amount of liters of 22% mixture must be equal to the amount of liters of 30% solution plus the amount of liters of 10% solution

Remember that

so

Solve for x

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0