In a reforestation program, 4250 seedlings were planted. three times as many hemlocks as spruces were planted. the number of oaks planted was 50 more than twice
the number of spruces. how many of each type of seedling was planted?
let x = the number of spruce seedlings. write an equation, in terms of x, for the 4250 seedlings that were planted.
=4250

The number of :  Spruce planted is  700

                            :Oaks  planted is  1450

                            :Hemlocks planted  is 2100

Step-by-step explanation:

Let the number of spruce planted = k

So,the number of hemlocks planted =  3k

And, the number of oaks planted = 50 + 2k

Total saplings planted = 4250

Now, Total saplings planted = Number of { spruce planted + oaks planted + hemlocks planted}

or, 4250 = k + 3k + (50 +2k)

⇒ 4250 - 50 = 6k

or, 6k = 4200

⇒ k =  (4200 / 6)  = 700  ⇒ k = 700

So, the number of spruce planted = 700

Number of Oaks planted = 50 + 2k = 50 + 1400 = 1450

ans, the number of hemlocks planted= 3k = 3 x 700 = 2100

its 69.420

step-by-step explanation:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743