Given a point on the terminal side of
functions of e.
trigonometry
(answer id # 0480248)
in standard position, find the exact value of the six trigonome
1. p(8, 2)
cot 8 =
sec @ =
sin
=
csc 8 =
cos 8 =
sec @ =
core -
sine =
sece -
2. p(-5, -1)
csc o =
cot @ =
csc b =
cose =
sine -
cos @ =
tan =
ane =
core
cos @ =
sine =
cose
sin e =
3. p(3,-8)
tan =
sece -
sec 0 =
esce
csc
=
sin 8 =
cot @ =
cos 6 =
4. p(9,-9)
cot 8 =
cos 8 =
tan 6 =
sin =
sec @ =
csc 8 =
p(-4,6)
tan 8 =
sece =
sec 8 =
sine -
sin 8
=
cote
cot 8 =
asce
csc
=
cose =
cos 6 =
6. p(-7, 7)
csc @ =
sin 0 =
tan 8 =
cot @ =
cos =
sec =
7. p(-1,-4)
tan 6 =
dan ?
see =
sec 2 =
cot 8 =
cote -
csc
see
=
sine =
sin 8 =
cose =
cos @ =
8. p(2,5)
tan 8 =
sec 8 =
csc 8 =
cot =
cos 8 =
sin 8 =
9. p(-6, 3)
cos 8 =
tan 8 =
csc @ =
cot 8 =
sec 0
=
sin @ =
10. p(3, 4)
cos 8 =
sec =
cot @ =
csc
=
tan 8 =
sin
=
4, 6, 8, 9