Every monday, marina eats one croissant and every tuesday she eats two croissants. on each subsequent day of the week, she eats a number of croissants equal to the sum of the croissants eaten on the two previous days, with the exception that if she eats more than four croissants on any particular day, the next day she will eat only one croissant. at the end of the week (which runs from monday through sunday), the cycle resets, and marina goes back to eating one croissant on monday, two on tuesday, and so forth. if a particular month begins on a wednesday, how many croissants will marina eat on the 22nd of that month?
(a) 1
(b) 2
(c) 3
(d) 5
(e) 6

The answer is option C : 3.

Step-by-step explanation:

Lets consider this table:

M    T   W   Th   F   Sa   Su   M    T   W

1      2    3     5    1    1      2     1     2     3

If the 1st of the month is a Wednesday, then the 6th of the month is a Monday and so are the 13th and 20th of the month.

So, on the 20th, Marina eats 1 croissant, on the 21st she eats 2 croissants, and on the 22nd, she will eat 1 + 2 = 3 croissants.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square