(25 points) suppose the probability of exposure to the flu during an epidemic is 0.6. a vaccine is 80% successful in preventing an inoculated person from acquiring the flu, if exposed to it. a person not inoculated faces a probability of 0.9 of aquiring the flu, if exposed to it. define the probability of at least one will be flue for a randomly selected person.

The probability of at least one person will catch the flu is 0.5952

Step-by-step explanation:

To find the probability of al least one catches the flu, we need to find the difference between 1 and the probability of not catching the flu.

The probability of catching the flu varies if the person is inoculated or not.

Let the events be:

E: the person was exposed

F: the person catches the flu

Hence, it is attached a tree diagram of the sample space. According to the diagram:

Inoculated person:

P(F')= 0.6×0.8 + 0.4×1 = 0.88 (We choose the second and the fourth way)

Not inoculated person:

P(F')= 0.6×0.1 + 0.4×1= 0.46 (We choose the second and the fourth way)

Let the events be:

= the person is inoculated and catches the flu

=the person is not inoculated and catches the flu

Using complementary events, DeMorgan’s Laws, and independence we have:

P(∪)=1-P(∪)'

=1 - P(∩)

=1 - P()×P()

=1 - (0.88)×(0.46)

=1 - 0.4048

=0.5952

The probability of at least one will catch the flu for a randomly selected person is 0.5952

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.  

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation: