Which point-slope equation represents a line that passes through (3, –2) with a slope of negative startfraction 4 over 5 endfraction?

y – 3 = –(x + 2)
y – 2 = (x – 3)
y + 2 = –(x – 3)
y + 3 = (x + 2)

answer:

y-3=-(x+2)

step-by-step explanation:

go through each question one by one by substituting in each x value and y value.

1) y-3=-(x+2)

-2-3=-(3+2)

-5=-5

since -5=-5, you don't have to go any further, this is your answer.   just remember that the points (3,-2) are set up in (x,y) so x=3 and y=-2

step-by-step explanation: s