The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. which the following equations could be used to find the smaller integer, n?

n+(n+2)+20=4n

Step-by-step explanation:

Let the smaller integer be n,

the bigger odd integer will be n+2.

n+(n+2)+20=4n

2n+22=4n

2n=22

n=11

answer: what is the conflict?

step-by-step explanation:

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