9. a rectangle has a width that is 2 feet longer than four times the length. what is the length of the rectangle
if the perimeter is 64 feet? (hint: draw a picture and use algebra to solve)

6 feet

Step-by-step explanation:

Perimeter = 2L + 2W

Since you know the perimeter is 64 feet, you would plug that into the perimeter side.

64 = 2L + 2W

You also know the width is 2 feet longer than 4 times the length.

64 = 2L + 2(2 + 4L)  > Multiply 2 * 2 and 2 * 4l

64 = 2L + 4 + 8L  > Subtract 4 from each side

-4           -4

60 = 2L + 8l > add these two

60 = 10L

/10   /10 > divide by 10 on each side

6 = L

Now that we know the length, find the width.

64 = 2(6) + 2(2 + 4(6)) > multiply 2 * 6 and 4 * 6

64 = 12 + 2(2 + 24) > add 24 and 2

64 = 12 + 2(26) > multiply 2 and 26

Before you go any further, you now know that the width is 26 feet. Continue solving.

64 = 12 + 52

64 = 64

Everything checks out.

The length is 6 feet and the width is 26 feet.

a line is an defined derm because it

a)contains an infinite number of points b) can be used to create other geometric shapes c)describes something that does not have width or depth d) is a term that does not have a formal definition. a line is an undefined term because it: contains an infinite number of points.

step-by-step explanation: