Aball is thrown into the air with a initial velocity of 25 meters per second. the function h(t)+-4.9t^2+25t+6 represents the height of the t in seconds. ball above the ground in meters, with respect to time. at h(3) then the height of the ball would be

36.9 m

Step-by-step explanation:

h(t) = -4.9t² + 25t + 6

At t = 3:

h(3) = -4.9(3)² + 25(3) + 6

h(3) = -44.1 + 75 + 6

h(3) = 36.9

After 3 seconds, the ball will have a height of 36.9 meters.

the answer to the question is a  

it has the same slope and the same y-intercept.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.