Acarton of two dozen eggs includes
three with cracks. how many eggs
without cracks can be expected in six
dozen eggs?

63

Step-by-step explanation:

A carton of 2 dozen (or 24) eggs have 3 eggs with cracks. This means that 3/24, or 1/8 of the the eggs have cracks.

Now, you are solving for six dozen eggs. 6 x 12 = 72. Multiply 72 with 1/8:

72 x 1/8 = 72/8 = 9

9 eggs are expected to have cracks out of 72.

However, you are solving for the amount of eggs without cracks. Subtract 9 from 72:

72 - 9 = 63

63 is your answer.

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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet