Given: b is the midpoint of segment a c. segment b c is congruent to segment d e. prove: segment a b is congruent to segment d e. art: three line segments a b, b c, and d e. line segments a b and b c make a straight line. line segment d e intersects line segment b c. point d lies on upward-left direction from line segment b c. statements reasons 1. b is the midpoint of ac. given 2. ab≅bc definition of midpoint 3. bc≅de given 4. ab≅de
what is the reason for statement 4 of the two-column proof? symmetric property of equality segment congruence postulate segment addition postulate transitive property of congruence

step-by-step explanation:

milk=16 large

soda=280 kids

juice box=82 regular

63 soda +63 regular

124 large total

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )

21

step-by-step explanation: