The lengths of the sides of a square are multiplied by 1.2. how is the ratio of the areas related to the ratio of the side lengths?

The ratio of the areas is equal to the ratio of the lengths squared

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor and the ratio of its areas is equal to the scale factor squared

In this problem

If the lengths of the sides of a square are multiplied by 1.2

then

the scale factor is 1.2

Remember that the ratio of the side lengths is equal to the scale factor

so

The ratio of the side lengths is equal to 1.2

and

The ratio of the areas is equal to the scale factor squared

so

The ratio of the areas is equal to 1.2^2

therefore

The ratio of the areas is equal to the ratio of the lengths squared

for any of you who need the translation here it is

step-by-step explanation:

find the angular size of the equatorial radius of the earth, if the horizontal parallax of the sun

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3