Quadrilateral jklm was dilated according to the rule do, one-half(x, y)(one-half x, one-half y) to create the image quadrilateral j'k'l'm', which is shown on the graph. on a coordinate plane, quadrilateral j prime k prime l prime m prime has points (0, negative 2), (3, 2), (6, negative 2), and (3, negative 6). what are the coordinates of vertex j of the pre-image? (0, -4) (0, -1) (0, 0) (0, 4)

493 would be the correct answer

step-by-step explanation:

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.