Astandard deck of cards is dealt to four players, each receiving thirteen cards. if the first player gets exactly five hearts, what is the chance the second player gets exactly four hearts?

0.000024

Step-by-step explanation:

If the first player gets exactly five hearts, there are 39 cards left, 8 of which are hearts.

So, the probability of getting one heart is 8/39, for the second heart the probability is 7/38 and 6/37 and 5/36 for the 3rd and 4th hearts.

There are still 4 hearts in the deck, and the probability of getting a non heart is (35-4)/35=31/35, (34-4)/34=30/34,..., (27-4)/27=23/27 for the next 9 cards.

As the event of taking a card is independent of the previous result, the probability the second player gets exactly 4 hearts is

(8/39)*(7/38)*(6/37)*(5/36)*(31/35)*(30/34)***(23/27)

= 0.000024

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers