Create the equation of a cubic in standard form that has a double zero at -2, another zero at 4, and a y-intercept of 16,

f(x) = x³ - 3x - 4

Step-by-step explanation:

Given that x = - 2 has multiplicity 2 and x = 4 are zeros then

(x + 2)² and (x - 4) are the factors of the polynomial and the polynomial is the product of the factors, thus

f(x) = a(x + 2)²(x - 4) ← a is a multiplier

To find a substitute (0, 16) into the equation

16 = a(4)(16), thus

64a = 16

a = =

f(x) = (x + 2)²(x - 4) ← expand factors

    = (x² + 4x + 4)(x - 4)

    = (x³ + 4x² + 4x - 4x² - 16x - 16)

    = (x³- 12x - 16)

   = x³ - 3x - 4

answer: i believe it’s 245.04

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!