We have data for two groups: college juniors represented by the subscript 1 and college seniors represented by the subscript 2. do a two-sample test for equality of means assuming unequal variances. minitab will be of great assistance. when exam-time rolls around, make certain that you are able to calculate tcalc by hand. (a-1) comparison of gpa for randomly chosen college juniors and seniors: x¯1x¯1 = 3.05, s1 = .20, n1 = 15, x¯2x¯2 = 3.25, s2 = .30, n2 = 15, α = .025, left-tailed test.

a) 7x=7

step-by-step explanation:

r and t.

both are 64 degrees.

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4