The random variable x, representing the number of items sold in a week, has the following probability distribution: x 0 1 2 3 4 5 6 p(x = x) 0.10 0.20 0.40 0.15 0.05 0.05 0.05 by the fourth day of a particular week, 3 items have already sold. what is the probability that there will be less than a total of 5 items sold during that week?

0.667

Step-by-step explanation:

Data provided:

x                0                1              2              3              4              5              6

P(X = x)    0.10         0.20         0.40         0.15         0.05         0.05         0.05

Now,

The probability that less than 5 items will be sold in a week given that 3 items have already been sold can be calculated as;

P ( less than 5 items sold | 3 or more items sold )

=

=

or

P ( less than 5 items sold | 3 or more items sold ) =

or

P ( less than 5 items sold | 3 or more items sold ) =

or

P ( less than 5 items sold | 3 or more items sold ) = 0.667

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !