Assume that human body temperatures are normally distributed with a mean of 98.22 degrees upper f 98.22°f and a standard deviation of 0.61 degrees upper f0.61°f. a. a hospital uses 100.6 degrees upper f100.6°f as the lowest temperature considered to be a fever. what percentage of normal and healthy persons would be considered to have a fever

0.00102%

Step-by-step explanation:

Given : Human body temperatures are normally distributed with a mean of and a standard deviation of

A hospital uses as the lowest temperature considered to be a fever.

Let x be the random variable that represents the human body temperatures.

For x= 100.6,

Using normal distribution table for z-values for right-tailed area ,

P(x>100.6)=

Hence, the required probability = 0.00102%

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: