Gonzalez manufacturing borrowed $33000. part of the money was borrowed at 8%, part at 10%, and part at 12%. the total amount borrowed at 8% and 10% was twice the amount borrowed at 12%. find the amount borrowed at each rate if the annual interest was $3360.

Answer

given,

borrowed money = $33000

Part of the money was borrowed at 8% be x, part at 10% be  y, and  part at 12% be ($33000-x-y)

x + y = 2 ($33000-x-y)

3 x + 3 y = $ 66000

x + y = $ 22000(1)

third part =$33000-($22000)

                = $ 11000

now annual interest is

0.08 x + 0.1 y +  0.12 × 11000 = $ 3360

0.08 x + 0.1 y = 2040(2)

0.1 x + 0.1 y = 2200(3)

solving equation (3) and (2)

x = $ 8000

y = $ 14000

3 rd number = $ 11000

so what is the question

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