Aresearcher wishes to conduct a study of the color preferences of new car buyers. suppose that 40% of this population prefers the color brown. if 18 buyers are randomly selected, what is the probability that exactly a third of the buyers would prefer brown? round your answer to four decimal places.

0.1655

Step-by-step explanation:

This is a binomial probability.

THe formula is:

Where n is the total number of people

r is how many we want (we want 1/3rd of 18 which is 6, r= 6)

p is probability of success (0.4)

Putting the information, we get:

Thus, the probability that exactly a third of the buyers would prefer brown is 0.1655

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

37

step-by-step explanation: