Asuspension bridge with weight uniformly distributed along its length has twin towers that extend 9090 meters above the road surface and are 16001600 meters apart. the cables are parabolic in shape and are suspended from the tops of the towers. the cables touch the road surface at the center of the bridge. find the height of the cables at a point 400400 meters from the center. (assume that the road is level.)

y = 22.5 m

Step-by-step explanation:

given,

length of the tower = 90 m

distance between the towers = 1600 m

height of cable at 400 m = ?

we know

y = a x²

x is the distance from the center where the cable is touching the ground

at the far end y = 90 m and x = 800

90 = a × 800²

now height at x = 400

y = 22.5 m

height of the cables at 400 m is equal to y = 22.5 m

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!