Aresearcher at a large company has collected data on the beginning salary and current salary of 48 randomly selected employees. the least-squares regression equation for predicting their current salary from their beginning salary is = –2532.7 + 2.12x. the current salaries had a mean of $32,070 with a standard deviation of $15,300. the beginning salaries had a mean of $16,340 with a standard deviation of $5970. what is the correlation between current and beginning salary? group of answer choices

0.8272

Step-by-step explanation:

given equation –2532.7 + 2.12x.

The regression equation of y on x is given by

where b_yx = correlation(x,y)×sd(y)/sd(x)

Comparing the given equation with the above form

b_yx = 2.12

=> r(x,y)×sd(x)/sd(y) =2.12

=> r(x,y)×5970/15300 = 2.12

=> r(x,y) = .8272

after simplifying it i got: -36.25 as my answer. hope that !

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d