Need

a stadium has 50,000 seats. seats sell for $30 in section a, $24 in section b, and $18 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,289,400 from each sold-out event. how many seats does each section hold?

Step-by-step explanation:

Section A comprises half the seats, so contains 26,500 seats.

The revenue from those is ...

  $28×26,500 = $742,000

so the revenue from the remaining seats is ...

  $1,118,800 -742,000 = $376,800

An equation for that can be written using "b" for the number of section B seats:

  16b +12(26,500 -b) = 376,800

  4b + 318,000 = 376,800

  b = (376,800 -318,000)/4 = 14,700

Then the remaining number of seats is the number in section C:

  26,500 -14,700 = 11,800

There are 26,500 seats in Section A, 14,700 seats in Section B, and 11,800 seats in Section C.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

the answer is d

step-by-step explanation: