Aflorist has 25 flower arrangements to sell. the amount of money the florist makes for selling x flower arrangements is represented by a function.

f(x)=15x

what is the practical domain of the function?

A florist has 25 flower arrangements to sell. Practical domain of f(x) = { x : x > 0 and x <= 25}.

Solution:

Number of arrangements of flower to sell = 25

Amount of money generated by selling flower = 15x where x represents flower arrangements.

So x can have possible values of 1 to 25

“x” cannot be zero or negative as it make no sense of counting flower arrangements as 0 or negative.

So practical value of x that is practical domain of f(x) = 15x is x = { 1 , 2 , 3 ,4 ……. 25 }

Or domain of f(x) = { x : x > 0 and x <= 25}

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

i use my brain for prombles like this maybe you could try it

step-by-step explanation: