Square a"b"c"d" is the final image after the rule was applied to square abcd. on a coordinate plane, a square a double-prime b double-prime c double-prime d double-prime has points (negative 5, negative 3), (negative 3, negative 1), (negative 1, negative 3), (negative 3, negative 5). what are the coordinates of vertex a of square abcd? (–1, –6) (–1, –2) (–1, 6) (–2, 1)

b

step-by-step explanation:

the word superfluous means unnecessary

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

y > 1/3x

y < = -x + 4

hope this : )

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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