He longer base of isosceles trapezoid is 12 cm. the side is 5 cm. the acute angle is 37º. find the shorter base.

The shorter base is 4.0136.

Given that,

Based on the above information, the calculation is as follows:

x = 5 cos 37

x = 3.9932 cm

Now  

The shorter base = longer base - 2(3.9932)

= 12 - 7.9864

= 4.0136

Therefore we can conclude that the shorter base is 4.0136.

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4.01 cm to the nearest hundredth.

Step-by-step explanation:

Consider the triangle formed by the perpendicular line drawn from one endpoint of the shorter base to the longer base.

cos 37 = x / 5

x = 5 cos 37

x = 3.9932 cm

The shorter base = longer base - 2(3.9932)

= 12 - 7.9864

= 4.0136

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .