The denominator of a rational number is greater than its numerator by 10. if the
numerator is increased by 19 and the denominator is decreased by 1. the number obtained is 3/2. find the original number.

The denominator of a rational number is greater than its numerator by 10. The required rational number is

Solution:

Let the numerator be x.

And, denominator = x + 10

hence the original fraction is

Given that numerator is increased by 19 and denominator is decreased by 1 then the fraction is equal to

Evaluate the above expression

2(x+19)=3(x+9)  

Multiply 2 with (x+19) and Multiply 3 with (x+9)

2x+38=3x+27

Keep x in one side and constant in other side. so that we can find the value of x.

2x-3x=27-38

-x= -11

Eliminating the ‘-‘sign

Therefore x=11.

Hence, required fraction =  

Hence the required number is

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

i will pick c put check it over to be sure

step-by-step explanation: