Aprojectile is shot into the air following the path, h(x) = -3x^2 + 30x + 300. at what time, value of x, will it reach a maximum height?
x = 1
x = 2
x = 4
x = 5

maximum at x=5

Step-by-step explanation:

This path is parabolic (represented by a parabola since it is given by a quadratic expression).The parabola has the branches down since its leading coefficient is negative (-3), so the maximum value of this function will correspond to the vertex of the parabola.

We can use the definition for the vertex of a parabola to find it.

For a general parabola of the form: ,

the x-value of its vertex is given by the expression:

In our case, (since = -3,  and = 30) it becomes:

Therefore, the projectile will reach its maximum at x=5

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.