Find the derivative of the vector function r(t)=ta×(b+tc)r(t)=ta×(b+tc), where a=⟨5,3,−4⟩a=⟨5,3,−4⟩, b=⟨−4,1,1⟩b=⟨−4,1,1⟩, and c=⟨−3,2,−4⟩c=⟨−3,2,−4⟩.

By the product rule,

We have

So

828. all there is to it!

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thats the rounding one, but if you just click the top left, it shows you all the calculators you may need!

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1