In a shipment of 56 vials, only 13 do not have hairline cracks. if you randomly select 3 vials from the shipment, in how many ways can at least one of the 3 selected vials have a hairline crack if the order of selection does not matter?

27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

Hence, the required number of ways =27434

because its not ur topic and its not for is for homework not that.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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