The sum of three numbers is 45. the second of the three numbers is three more than twice the first number. the third unter
is two more than the first number, x. which eguation can be used to solve for the first number,
x + 5x + x + 2 = 45
x+x+3+x+ 2 = 45
x + 3x + 2 + x + 2 = 45
x + 2x + 3 + x + 2 = 45
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x + 5x + x + 2 = 45

x + 3 + 2x + 2 + x = 45

Step-by-step explanation:

Let the three numbers be x, y and z

If the sun of the three numbers is 45;

x+y+z = 45 ... (1)

If the second of the three numbers which is 'y' is three more than twice the first number 'x', this is expressed as:

y = 3+2x ... (2)

Also if the third number 'z' is two more than the first number 'x', this is expressed as:

z = 2+x ...(3)

To get the equation that can be used to solve for the first number 'x', we will substitute equation 2 and 3 into equation 1 to have;

x + (3+2x) + (2+x) = 45

= x + 3 + 2x + 2 + x = 45

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could