The height of 5th grade boys is normally distributed with mean μ=57 inches and standard deviation σ=2 inches. what is the probability that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches?

0.9544

Step-by-step explanation:

Mean =  μ=57

Standard deviation σ=2

Formula :

At x = 53

Refer the z table

P(z<-2)=0.0228

At x = 61

Refer the z table

P(z<2)=0.9772

We are suppose to find the probability that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches.

P(53<x<61)=P(-2<z<2)=P(z<2)-P(z<-2) = 0.9772 - 0.0228=0.9544

Hence the probability that the height of a randomly selected 5th grade boy will be between 53 inches and 61 inches is 0.9544

do you have the measurements?

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.