Aprojectile is fired upward from the ground with an initial velocity of 300 feet persecond. neglecting air resistance, the height of the projectile at any time t can bedescribed by the polynomial function p(t) = ­16t2 + 300

a. find the height of the projectile when t = 1 second.
b. find the height of the projectile when t = 5 seconds.
c. how long will it be until the object hits the ground?

P(t) = - ­16t*2 + 300t

For t = 1 second we have:

P(1) = - 16*1^2 + 300*1

P(1) = 284 ft

The height of the projectile after 1 second is 284 feet.

Step-by-step explanation:

Hope this helps :))

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .