One pack of biscuits cost $x and one cup of ice cream costs $y. one packet and 2 cups of ice cream costs $8, while three packet of biscuits and one cup of ice cream cost $9. by solving determine the cost of both items

One pack of biscuits cost $x and one cup of ice cream costs $y. The cost of both the items are x = 2 and y = 3

Solution:

By solving determine the cost of both items

Step 1:

Say Biscuits=x and ice cream=y

Therefore: 1 pack biscuit and 2 cups ice cream = x+2y=8

3 pack biscuit and 1 cup ice cream = 3x+y=9

Step 2:

x+2y=8 (i)

3x+y=9 (ii)

Step 3:

To solve:

From equation i, x=8-2y

Substituting into (ii),

3(8-2y)+y=9

24-6y+y=9

24-5y=9

-5y=-15

y=3

Step 4:

To find x:

Place y=3 into (i)

x+2y=8

x+2(3) =8

Step 5:

x+6=8

x=8-6

x=2

Hence the cost of both the items biscuit and icecream is 2 and 3

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: