What is the vertex for the graph of y-3 = - (x + 2)2
o a (3-2)
o b. (23)
o c. (23)
o d. (-3.2)

(-2, 3)

Step-by-step explanation:

y - 3 = -(x + 2)^2 is in point slope form:

y - k = a(x - h)^2

with the point (h, k) being the vertex.

(h, k) is (-2, 3).

Your options aren't written correctly as coordinates

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

step-by-step explanation: s