Maximum likelihood and map estimation (4 pts): of the exponential distribution p(x) = λ exp(−λx) , x ≥ 0 0, , x < 0 (1) from a set of measurements of x, specified by xn; i = 1, 2, n. assume that the prior is given by p(λ) = α exp(−αλ) , λ ≥ 0 0, , λ < 0 (2) (a) determine the expression for the maximum likelihood estimate of the parameter λ from xn; i = 1, 2, n. (b) determine the expression for the map estimate of the parameter λ from xn; i = 1, 2, n.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

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< 3

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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