Gabriel operates riverboat and frequently offers tours of the river. typically, a tour lasts for 3.25 hours. the riverboat ssually takes 2.00 hours to make the 25- mile trip from the dock and 1.25 hours to make the 25/ mile return trip doenstream. gabriel is considering offering a shoorter tour that will last 2/50 hours and travel only 20 miles upstream before returning. will the shorter tour be possible if the riverboat travels at ther same speed as it does in the 3.25- hour tour?

The shorter tour is not possible.

Step-by-step explanation: For this problem, we dont even need to find R and S because we have a lot of information already given to us. On the way up, the boat travels at 25/2mph which translates to 12.5mph. On the way down, the boat travels at 25/1.25mph which translates to 20mph. Since the tour is 20 miles, we can calculate the amount of time that the tour will take.  Time up:20/1,25=1.6 hours. Time down:20/20= 1 hour. When we add those up, we get 2.6 hours which is more than the desired 2.5 hours. That is why the shorter tour is not an option.

(3x-8) or (3x+8)

step-by-step explanation:

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation: