Sony would like to test the hypothesis that the average age of a playstation user is different from the average age of an xbox user. a random sample of 36 playstation users had an average age of 34.2 years while a random sample of 30 xbox users had an average age of 32.7 years. assume that the population standard deviation for the age of playstation and xbox users is 3.9 and 4.0 years, respectively. sony would like to set α = 0.10. which one of the following statements is true?

(a) because the p-value is less than α, we reject the null hypothesis and can conclude that the average age of playstation users is different from the average age of xbox users.
(b) because the p-value is less than α, we fail to reject the null hypothesis and conclude that the average age of playstation users is equal to the average age of xbox users.
(c) because the p-value is greater than α, we fail to reject the null hypothesis and cannot conclude that the average age of playstation users is different from the average age of xbox users.
(d) because the p-value is greater than α, we fail to reject the null hypothesis and can conclude that the average age of playstation users is different from the average age of xbox users.

(C) Because the p-value is greater than α, we fail to reject the null hypothesis and cannot conclude that the average age of PlayStation users is different from the average age of Xbox users.

Step-by-step explanation:

The t-statistic for difference of mean is given by,

Using this formula, we get, t = 1.5342

Thus, p-value = 0.1322 with 64 degree of freedom.

and α = 0.10

Since, the p-value is greater than alpha (p > .05), then we fail to reject the null hypothesis, and we say  that the result is statistically non-significant.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497