If the angle of the incline is less than the limiting angle of repose, which of these statements is true? [ ] fs = the coefficient of static friction multiplied by the normal force [ ] fs > the coefficient of static friction multiplied by the normal force [ ] fs < the coefficient of static friction multiplied by the

If the angle of the incline is less than the limiting angle of repose: fs < the coefficient of static friction multiplied by the normal force

Step-by-step explanation:

The friction force is variable and will depend on the external reactions.

If a body is over an inclined plane with an angle less than the limiting angle of repose, the friction force (fs) will increase as a function od the angle of inclination and will be equal to the body's weight projection parallel to the plane.

At the limiting angle of repose the friction force will be equal to the coefficient of static friction times the normal force (after that point, the body will start to slide down the plane), but at any angle less than that the friction force will always be less than the named multiplication.

Note that the coefficient of the static friction can be calculated as the tangent of the limiting angle of repose.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!