Jeff has a beagle that is 2 feet,6 inches long. the longest lizard was 13 feet,1 inch longer than jeff's beagle. how long was the longest lizard ever discovered?

The length of the lizard is 187 inches

Solution:

It is given that Jeff’s beagle is 2 feet 6 inches long.

Le the length of the longest lizard be x.

We first convert 2 feet 6 inches into inches.

We know,

1 feet =12 inch  

2 feet = 12 2 = 24 inch

2 feet 6 inches = 24 + 6 = 30 inches

Similarly,

13 feet = 13 12 = 156 inches.

13 feet 1 inch = 156 +1 = 157 inches

According to question the longest lizard is 13 feet 1 inch or 157 inch longer than Jeff’s beagle.

Length of the lizard = 157 +30 = 187 inch

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204