Evaluate the following integrals showing each step. displaymode int x e^x dx. displaymode int x sin 2x dx. displaymode int e^(-x) x^2 dx. displaymode int [ln x]/[x^2] dx. find the center of mass of the region bounded by y = sin x between x = 0 and x = pi above the x-axis. displaymode integral from 0^pi t sin 2t dt. displaymode integral from (0)^(pi^2n^2) sin root(x) dx. (first substitution, then by parts)

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

where does the z at is it on the x axes or on the y axes any way if it is on the y axes put it horizontally and if it is on the x axes put it vertically