Factor the following polynomial by grouping:

Step-by-step explanation:

The answer is C.  I have never had to rearrange the terms when factoring by grouping, but here I had to in order to get it to work.  Rearranging makes the polynomial become:

3yz² + 6y³ - 4y²z - 2z³

Grouping:

(3yz² + 6y³) - (4y²z - 2z³)

Factoring out a 3y from the first term and a 2z out of the second term gives us:

3y(z² + 2y²) - 2z(2y² + z²)

Because addition is commutative, the terms inside the parenthesis are the same.  We can factor that out now, leaving in another set of parenthesis what is left:

(2y² + z²)(3y - 2z)

That is C.

answer: asdfghjkl,mnbv

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1