Josue's dogs:
sara's dogs:
morning
morning
26.21.15, 35, 38, 16, 13, 28, 30,25 39,21, 12,27, 23, 19, 19.31, 36,25
afternoon:
15, 12. 9. 7. 44, 23, 55, 10, 37,35
afternoon:
15,51, 8, 16, 43, 34, 27. 11.8,39
1. which dog-walker did you select? circle one.
josue
sara
comparing the morning and afternoon groups
2. create frequency tables to represent the morning and afternoon dogs as two sets of data. group the
weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for
correctly portraying data)

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

the graph on the bottom right

step-by-step explanation:

multiple all that

step-by-step explanation:

27×17