Using a directrix of y=-2 and a focus of (2,6), what quadratic function is created?

a. f(x)=-1/8(x-2)^2-2
b. f(x)=1/16(x-2)^2+2
c. f(x)=1/8(x-2)^2-2
d. f(x)=-1/16(x+2)^2-2

  B.  f(x)=1/16(x-2)^2+2

Step-by-step explanation:

The equation can be written as ...

  f(x) = 1/(4p)(x -h)^2 +(k-p)

where (h, k) is the focus, and p is half the distance between focus and directrix. Here, (h, k) = (2, 6) and p=(6-(-2))/2 = 4. So the equation is ...

  f(x) = 1/16(x -2)^2 +2

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The graph shows the focus, directrix, and parabola. It also shows the parabola is the set of points that are the same distance from focus and directrix. (Dashed orange lines are the same length.)

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!