Use the information below for questions 5 - 11. let x denote the number of telephone lines in use at an online business. suppose there are 6 lines and p(0) = .1, p(1) = .15, p(2) = .2, p(3) = .25, p(4) = .2, p(5) = .06, and p(6) = .04. first, construct the probability distribution table and derive the cumulative distribution function and use both the answer the following questions. question 8: probability that between 2 and 5 lines, inclusive, are not in use.

Step-by-step explanation:

Given that  X denote the number of telephone lines in use at an online business.

The variable x can take values from 0 to 6 and the probability can be tabulated as follows:  Cumulative probability is the Prob =P(X<=x)

We want prob that between 2 and 5 lines, inclusive not in use

This is equivalent to

1-

=

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !