Apopulation of bacteria is introduced into a culture. the number of bacteria p can be modeled by p(t) = 800 1 + 9t 90 + t2 , where t is the time in hours since the bacteria was introduced. find the rate of change of the population (in bacteria per hour) after 6 hours. (round your answer to one decimal place.)

Hello mate!

you know that the equation is (or at least i think this is):

p(t) = 800 + 9t/90 + t^2

You want to know the "rate of change" after 6 hours.

We know that the rate of change is the derivative of P(t) with respect to t; this is

now we want the rate of change when t = 6, then we replace t by 6 in the derivate equation:

so the rate of change after 6 hours is 12.9

where

If the equation is wrong ( because you write P(t) = 800 1 + 9t 90 + t2, and i don really know how to iterprete it) tellme and we can do the derivate again :D

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.