Aphysical fitness association is including the mile run in its secondary-school fitness test. the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 450 seconds and a standard deviation of 50 seconds. find the probability that a randomly selected boy in secondary school will take longer than 335 seconds to run the mile.

a) 0.5107

b) 0.9893

c) 0.0107

d) 0.4893

The probability that a randomly selected boy in secondary school will

take longer than 335 seconds to run the mile is 0.9893 ⇒ answer B

Step-by-step explanation:

- A physical fitness association is including the mile run in its

  secondary-school fitness test

- The time for this event for boys in secondary school is known to

  possess a normal distribution with a mean of 450 seconds and a

  standard deviation of 50 seconds

∴ μ = 450 seconds

∴ σ = 50 seconds

- We need to find the probability that a randomly selected boy in

  secondary school will take longer than 335 seconds to run the mile

- We must to find z-score for x > 335 seconds

∵ z = (x - μ)/σ

∵ x = 335 seconds , μ = 450 seconds , σ = 50 seconds

- substitute the values in the rule above

∴ z = = -2.3

- Use the normal distribution table of z to find the corresponding area

  of z-score

∵ P(-2.3) = 0.01072

- We need to find the area to the right of the z-score

∴ P( x > 335) = 1 - 0.01072 = 0.9893

* The probability that a randomly selected boy in secondary school

  will take longer than 335 seconds to run the mile is 0.9893

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5